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Squirt
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Post subject: SRF Howework fun time >_>  Posted: Mon Aug 29, 2011 2:58 pm |
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Help please >_>.
I was placed in AP calc AB and have summer work but I suck at math horribly Don't know what the hell this is asking D=
Givn f(t)= C e ^-kt
1.) If f(0) = 5 what is the value of C?
2.) If f(3)= 6, What is the value of k
There are two variables but I can only plug in one, what is this witch craft ?!
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woutR wrote: Squirt, you're a genius when it comes to raping women.
Last edited by Squirt on Mon Aug 29, 2011 5:12 pm, edited 1 time in total.
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MrJoey
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Post subject: Re: SRF Howework fun time >_> Posted: Mon Aug 29, 2011 3:13 pm |
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If you suck at math, why are you in an AP class?
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Quoted from BuDo
(Except I Am Vegeta cuz we all know he is a used tampon when it comes to his personality)
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Squirt
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Post subject: Re: SRF Howework fun time >_> Posted: Mon Aug 29, 2011 3:21 pm |
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Because public schools are retarded and won't switch me out is why.....
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woutR wrote: Squirt, you're a genius when it comes to raping women.
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woutR
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Post subject: Re: SRF Howework fun time >_> Posted: Mon Aug 29, 2011 3:42 pm |
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SM-Count
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Post subject: Re: SRF Howework fun time >_> Posted: Mon Aug 29, 2011 3:45 pm |
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If you plug in 0 for t for the first one then k doesn't matter, c=5. You should be able to do the second one.
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Squirt
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Post subject: Re: SRF Howework fun time >_> Posted: Mon Aug 29, 2011 4:22 pm |
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Can someone explain why its 5? ( Sorry haven't done math in like 3 months....) and can you do number 2 step by step please =(
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woutR wrote: Squirt, you're a genius when it comes to raping women.
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aznronin
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Post subject: Re: SRF Howework fun time >_> Posted: Mon Aug 29, 2011 4:56 pm |
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Is answer to the second one: k = -1/3 ln 6/5 ?
f(t) = C e^-kt
f(0) = 5
f(0) = C e^0 = 5
f(0) = C = 5
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takolin
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Post subject: Re: SRF Howework fun time >_> Posted: Mon Aug 29, 2011 5:00 pm |
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For the 1st one.
5=Ce^(-kt) (T = 0)
5=Ce^(-k*0)
5=Ce^0
5=C (any number raised to the zeroth power equals 1)
For the 2nd one, I assume c still equals 5 (from step 1) and thus you need to solve the following equation.
6=5e^(-3k)
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SM-Count
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Post subject: Re: SRF Howework fun time >_> Posted: Mon Aug 29, 2011 5:02 pm |
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No, F'(t) = f(t), for the second one you have to use the first derivation of F(t) for the plugging, assuming he didn't just screw up capitalization.
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Squirt
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Post subject: Re: SRF Howework fun time >_> Posted: Mon Aug 29, 2011 5:09 pm |
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| Forum God |
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They are all lower case >_>
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woutR wrote: Squirt, you're a genius when it comes to raping women.
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SM-Count
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Post subject: Re: SRF Howework fun time >_> Posted: Mon Aug 29, 2011 5:11 pm |
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You'll want to edit that, F(t) and f(t) are not the same thing. Oh yeah, forgot to put my solutions, I knew I was forgetting something: 1)  2) 
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takolin
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Post subject: Re: SRF Howework fun time >_> Posted: Mon Aug 29, 2011 5:14 pm |
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SM-Count wrote: You'll want to edit that, F(t) and f(t) are not the same thing. Back to my solution? Well the other option would be solve "6=Ce^(-3k)" while not specifying C, though you'll need to say that C can't be 0.
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Squirt
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Post subject: Re: SRF Howework fun time >_> Posted: Mon Aug 29, 2011 5:17 pm |
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Yeah it says using answer from part 1 for use in the question 2
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woutR wrote: Squirt, you're a genius when it comes to raping women.
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SM-Count
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Post subject: Re: SRF Howework fun time >_> Posted: Mon Aug 29, 2011 5:17 pm |
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Yeah, you and azn were right, it's just plugging. I just assumed since it's calculus homework there'd be calculus XD
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