doplertin wrote:
um guys unless im mistaken u all have it incorrect..?
if the probability of a stun on the first hit is independent of the probability of a stun on the second hit then this is known as "independent probabilities". This means you can either stun on the first hit or on the second. In which case the total probability is 30%+30% = 60%. that is on average out of every say 10 use sof this skill, you would stun 6 out of 10 times? eithe ron the first or second strike of each of those 10 hits.
However, if the probabiltiy of the first stun depends on the second stun. meaning that you have to have both stun at a 30% chance each before the ending effetct is a stun, then these are known as dependant probabilities. then the chance of a stun at the end, defined as both blows hitting in the 30%, is a multiplication = 30% x 30% = 9%.
i am thinking it is the former (the independent probability type)
that 51% figure is a calculation of the probability of not stunning if in fact the 2 strikes were dependant probabiltiies. you see if they were dependant then you have 4 outcomes :-
1 stun 2 no stun: 0.3 x 0.3 =9%
1 stun 2 stun: 03 x 0.7 =21%
1 no stun 2 stun: 0.7 x 0.3 =21%
1 no stun 2 no stun: 0.7 x 0.7 = 49% (of which the 51% re[resents a stun outcome)
So that 51% is only one of the four outcomes (the last one). The other probabiltiies still need to be added in but only if they are dependant.
so do we know if they are dependent or independent outcomes?
Your "dependent" outcomes there are actually calculated assuming each hit is independent. Those are actually the 4 possible results of taking these two events. Notice: 9+21+21+49=100%
The simplest way to determine if an event will occur in two hits is 1-(% not occur at all) which is 51%
I think you're just a little confused with your stats there.
Either way, I think Bake is prolly right about the skill having a 30% chance as a whole of stunning.