Not sure if you actually need help (Math that people learn probably around 8th grade?) or not but I will state the steps below.
9+3=12 12*2=24 48/24=2
PEMDAS
Take a hint...
lol @ everyone who voted for 2
I still stand by it. I understand it can be 288 but the way it is displayed implies otherwise.
with it being 2(9+3) it is implied that it is one term therfor it would be solved first. If it was 48/2*(9+3) implies the 2 is no longer part of the parentheses (48/2)(9+3) for that matter.
Joined: Feb 2009 Posts: 1751 Location: In your house, stealing your Dew.
Amarisa wrote:
UnbeatableDevil wrote:
2(9+3) and 2*(9+3) are the same thing, like how 5n and 5*n are the same thing...
Would 48/5(n) be any different than 48/5*n no
the difference is that 2*(9+3) implies they are no longer the same term.
16/2X
if x = 2+2
do you do 16/2*(2+2) = 8(2+2)?
The difference is that there is no variable in the original equation. So there is no reason to distribute the 2 among the 9 and 5, the 2 can stand alone where 2(9+x) cannot.
2(9+3) and 2*(9+3) are the same thing, like how 5n and 5*n are the same thing...
Would 48/5(n) be any different than 48/5*n no
the difference is that 2*(9+3) implies they are no longer the same term.
16/2X
if x = 2+2
do you do 16/2*(2+2) = 8(2+2)?
Of course you do, I've gotten so many points off math over many years typing that into my calculator and forgetting to add parenthesis. You would do 16/2 then 8*X if it's written like that. You have to write 16/(2X) if you want the other way, that's just how math works. Btw, everytime you use the word 'implies', you should really be saying 'implies to me'.
First of all, let's start talking about PEMDAS. P - Parenthesis E - Exponents M - Multiplication D - Division A - Addition S - Subtraction.
PEMDAS is not necessarily right. You don't do multiplication first over division unless it is in a parenthesis. You do whichever operation comes first.
So, let's use 48÷2(9+3). First you obviously do the parenthesis. 48÷2*12 Now, you divide 48 by 2, NOT 2 multiplied by 12. As I stated above, you do whichever operation comes first (Multiplication or Division). In this matter, division comes first. So, you divide 48 by 2.
I did that thursday in Math. Well I think it's that. Basically the line of a graph kept going on but would never touch 1 (on x). Thing is, it's such a farked up notion that the calculator will just assume the answer is 1.
I did that thursday in Math. Well I think it's that. Basically the line of a graph kept going on but would never touch 1 (on x). Thing is, it's such a farked up notion that the calculator will just assume the answer is 1.
Yep, that's called a limit. .999... can also be represented as an infinite geometric series that converges to 1.
True. Here's a fun (yet incorrect) way to prove. Let .999.... = x 10x = 9.99999.... 10x - x = 9x. 9x = 9.9999999... - .9999999... 9x = 9 x = 1 x = .999.... .999.... = 1
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A real way to prove it is represent .999... as an infinite geometric series (9/10)(1/10)^n from 0 to infinity. Common ratio = 1/10, a = (9/10). A geometric series converges to a/(1-r). (9/10)/(1-(1/10)) = 1. Therefore: .999.. = sum from 0 to infinity of (9/10)(1/10)^n = 1.
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Crumpets for Pres
otherwise, you are screwded on the rest calculation you do in your life...
